A. capacity (inner tube-system)

q: 1m (tube) = ?l (contrast-fluid)
100 × A (tube) = x l (contrast-fluid);
A (tube) = 0,3² cm × 3,14 = 0,2826 cm²
100 × 0,2826 cm² = 28,26 cm³ = 28,26 ml
= 0,02826 l
a: 1m (tube) = 0,02826 l

q: capacity of one line
c (line) = 17 cm + 13 cm + 30 cm × 2 = 90 cm
120 windings
90 cm × 120 = 10800 cm = 108 m
108 m × 0,02826 l = 3,05208 l
a: one line = 3,05208 l
q: capacity of ten lines = 30,5208 l
108 m × 10 (lines) = 1080 m
1080m × 0,02826 = 30,5208 l

q: communicative capacity Machine DN.
10 lines = 1080m tube
10 lines = 30,5208 l
capacity: 30,5 l
(For the further calculation we take 31 liters, to
include the deficit of contrast fluid in transitions.)
a: communicative capacity Machine DN (tube): 31 l


B. capacity (fluid-reservoir)

q: fluid-reservoir = ?l (contrast-fluid)
V(fluid-reservoir) = (14 + 12) : 2 × 124 × 30
V(fluid-reservoir) = 48360 cm³ = 48,36 l
a: capacity der Machine DN (fluid-reservoir): 48,36 l


C. velocity Machine DN

q: velocity and amount (drip)
velocity (optional):
assumption: 3 drops/min
180 drops/h
4320 drops/day
1 drop = 0,05 ml
20 drops = 1 ml
4320 drops = 216 ml = 0,216 l
a: velocity 4320 drops/day
a: amount 0,216 l/day


D. communicative duration Machine DN

q: communicative duration Machine DN
communicative capacity Machine DN = 31l
0,216 l = 1 day
31 l = x days
x = 31 : 0,216 = 143,51851 days

A: Communicative duration Machine DN: 143,5 days.